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amosova98
@amosova98
July 2021
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Решите неравенство x^2+11/2x-3>0
ПОЖАЛУЙСТА :(
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lown
x^2+11/2x-3>0
x^2+(11/2)x-3=0
D =121/4 +12 =169/4 =13/2
x1=(-11/2-13/2)/2= -6
x2=(-11/2+13/2)/2 =1/2
(x+6)(x-1/2)=0
(x+6)(x-1/2)>0
+ 0 - 0 +
---------!---------!---------
-6 1/2
(-бесконеч;-6)U(1/2;+бесконечн)
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Answers & Comments
x^2+(11/2)x-3=0
D =121/4 +12 =169/4 =13/2
x1=(-11/2-13/2)/2= -6
x2=(-11/2+13/2)/2 =1/2
(x+6)(x-1/2)=0
(x+6)(x-1/2)>0
+ 0 - 0 +
---------!---------!---------
-6 1/2
(-бесконеч;-6)U(1/2;+бесконечн)