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rgfwerfgefg
@rgfwerfgefg
March 2022
1
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представить в виде многочлена:
1) ((x+2)-(x-1))^2
2) (x+1)^2-2(x-1)^2
3) (1/2x-4a)^2
4) (4a+(x+2))^2
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Answers & Comments
saha0901
1) ((x+2)-(x-1))²=(x+2)²+2×(x+2)×(x-1)-(x-1)²=х²+4+2х²-2х+4х-4-х²-1=3х=2х²+2х-1
2) (x+1)²-2(x-1)²=х²+1-2×(х²-2х+1)=х²+2х²-4х-2=3х²-4х-2
3) (
x-4a)²=
-2ах+4а²
4) (4a+(x+2))²=16а²+2×4a×(x+2)+(х+2)²=
16а²+8ах+16а+х
²+4х+4
2 votes
Thanks 1
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Answers & Comments
2) (x+1)²-2(x-1)²=х²+1-2×(х²-2х+1)=х²+2х²-4х-2=3х²-4х-2
3) (x-4a)²=-2ах+4а²
4) (4a+(x+2))²=16а²+2×4a×(x+2)+(х+2)²=16а²+8ах+16а+х²+4х+4