представить в виде многочлена: 1) ((x+2)-(x-1))^2 2) (x+1)^2-2(x-1)^2 3) (1/2x-4a)^2 4) (4a+(x+2))^2. Created by rgfwerfgefg. geometriya-ru

1) ((x+2)-(x-1))²=(x+2)²+2×(x+2)×(x-1)-(x-1)²=х²+4+2х²-2х+4х-4-х²-1=3х=2х²+2х-12) (x+1)²-2(x-1)²=х²+1-2×(х²-2х+1)=х²+2х²-4х-2=3х²-4х-23) (x-4a)²=-2ах+4а²4) (4a+(x+2))²=16а²+2×4a×(x+2)+(х+2)²=16а²+8ах+16а+х²+4х+4

2x-4a)^2 4) (4a+(x+2))^2...

rgfwerfgefg @rgfwerfgefg

March 2022 1 11 Report

представить в виде многочлена:
1) ((x+2)-(x-1))^2
2) (x+1)^2-2(x-1)^2
3) (1/2x-4a)^2
4) (4a+(x+2))^2

Answers & Comments

saha0901 1) ((x+2)-(x-1))²=(x+2)²+2×(x+2)×(x-1)-(x-1)²=х²+4+2х²-2х+4х-4-х²-1=3х=2х²+2х-1
2) (x+1)²-2(x-1)²=х²+1-2×(х²-2х+1)=х²+2х²-4х-2=3х²-4х-2
3) ( $\frac{1}{2}$ x-4a)²= $\frac{1}{4}$ -2ах+4а²
4) (4a+(x+2))²=16а²+2×4a×(x+2)+(х+2)²=16а²+8ах+16а+х²+4х+4

Answers & Comments

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