[tex]2 {x}^{2} + 7x + 6 = 0 \\ a =2 \\ b =7 \\ c = 6 \\ D = {b}^{2} - 4ac = 49 - 4 \times 2 \times 6 = 49 - 48 = 1 \\ x_{1} = \frac{ - 7 - 1}{2 \times 2} = - \frac{8}{4} = - 2\\ x_{2} = \frac{ - 7 + 1}{2 \times 2} = - \frac{6}{4} = - 1.5 \\ \\ a {x}^{2} + bx + c = a(x - x_{1})(x - x_{2}) \\ 2 {x}^{2} + 7x + 6 = 2(x + 2)(x + 1.5)[/tex]

Ответ:

вот, все на картинке####