вариант 1) y'= ctgy-√4x -1 2) xy' = 4√/2x² + y² + y 3) (xy'-1). In x = 2y, y(e) = 0 4) y" - 4y' +8y=0. Created by destradesreynaldo.

2x² + y² + y 3) (xy'-1). In x = 2y, y(e) = 4) y"

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вариант 1) y'= ctgy-√4x -1
2) xy' = 4√/2x² + y² + y
3) (xy'-1). In x = 2y, y(e) = 0
4) y" - 4y' +8y=0

HSS9860

Пошаговое объяснение:

посмотрите решение для №№3 и 4.

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