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gukam
@gukam
July 2022
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(1/2*2^1/2)^x+1=4^1-x
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fiofionina
Verified answer
Решение:
(1/2*2^1/2)^x+1=4^1-x
(2^-1*2^1/2)^(x+1)=(2^2)^(1-x)
[2^(-1+1/2)]^(x+1)=2^(2-2x)
(2^-1/2)^(x+1)=2^(2-2x)
2^(-x/2-1/2)=2^(2-2x)
-x/2-1/2=2-2x Приведём уравнение к общему знаменателю 2
-х-1=2*2-2*2х
-х-1=4-4х
-х+4х=4+1
3х=5
х=5 : 3
х=5/3
Ответ: х=5/3
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Verified answer
Решение:(1/2*2^1/2)^x+1=4^1-x
(2^-1*2^1/2)^(x+1)=(2^2)^(1-x)
[2^(-1+1/2)]^(x+1)=2^(2-2x)
(2^-1/2)^(x+1)=2^(2-2x)
2^(-x/2-1/2)=2^(2-2x)
-x/2-1/2=2-2x Приведём уравнение к общему знаменателю 2
-х-1=2*2-2*2х
-х-1=4-4х
-х+4х=4+1
3х=5
х=5 : 3
х=5/3
Ответ: х=5/3