Ответ:
(2x+1)(x+2)-(x-1)(3x+1)=1
2x^2 + x + 4x + 2 - 3x^2 + x - 3x - 1 = 1
x^2 - 7x - 2 = 0
a=1 b=-7 c=-2
x1 = = =
x2===
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Ответ:
(2x+1)(x+2)-(x-1)(3x+1)=1
2x^2 + x + 4x + 2 - 3x^2 + x - 3x - 1 = 1
x^2 - 7x - 2 = 0
a=1 b=-7 c=-2
x1 =
=
=
x2=
=
=