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ladykurchenko0
@ladykurchenko0
July 2022
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Найдите интервал возрастания функции y=1/2x^2-4x+1.
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abddilagg
-b\2a = -4+1= -3
1\2* (-3)^2 - 12 + 5 =
512+5=9.5-12=-2.5
х= -3
х=0 у=5
х=1 у=9.5
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Answers & Comments
1\2* (-3)^2 - 12 + 5 =
512+5=9.5-12=-2.5
х= -3
х=0 у=5
х=1 у=9.5