x^3 + 2x^2 - 4x^2 - 8x + 2x +4 = 0 x^2 (x+2) - 4x (x+2) + 2 (x+2) = 0 (x+2) (x^2 - 4x +2) = 0 x+2 = 0; x^2 - 4x + 2 = 0; x = -2; x = 2 + корень(2); x = 2 - корень(2)
По теореме Виета
х1+х2=3
х1*х2= 2
х=1 х=2
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Answers & Comments
x^3 + 2x^2 - 4x^2 - 8x + 2x +4 = 0
x^2 (x+2) - 4x (x+2) + 2 (x+2) = 0
(x+2) (x^2 - 4x +2) = 0
x+2 = 0; x^2 - 4x + 2 = 0;
x = -2; x = 2 + корень(2); x = 2 - корень(2)
По теореме Виета
х1+х2=3
х1*х2= 2
х=1 х=2