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qowshjsis
@qowshjsis
July 2022
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(2+√x)×(2−√x)+√x найдите производную, срочно
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sedinalana
(2+√x)×(2−√x)+√x=4-x+√x
(4-x+√x)`=-1+1/2√x
0 votes
Thanks 1
qowshjsis
откуда 1/2 корень из х?
MySoulCry1
Преобразуем
(2+√x)×(2−√x)+√x=4-х+√х
(4-х+√х)'=0-1+½х^-½=-1+1/(2√х)
1 votes
Thanks 1
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Answers & Comments
(4-x+√x)`=-1+1/2√x
(2+√x)×(2−√x)+√x=4-х+√х
(4-х+√х)'=0-1+½х^-½=-1+1/(2√х)