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ainura0205
@ainura0205
June 2022
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(2x+3)(3x+1)-10=11x+20
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manyny06
Verified answer
2x*3x+2x*1+3*3x+3*1 -10 = 11x +20
6x²+2x+9x+3-10-11x-20=0
6x²-27=0
3 (2x²- 9)=0
3(x√2-3)(x√2+3)=0
произведение равно нулю когда один из множителей равен нулю
х√2-3 = 0 ⇒ х= 3\√2 х₁= 3√2\2
или
х√2+3=0 ⇒ х= - 3\√2 х₂ = -3√2\2
1 votes
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ainura0205
СпасибоҚ
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Answers & Comments
Verified answer
2x*3x+2x*1+3*3x+3*1 -10 = 11x +206x²+2x+9x+3-10-11x-20=0
6x²-27=0
3 (2x²- 9)=0
3(x√2-3)(x√2+3)=0
произведение равно нулю когда один из множителей равен нулю
х√2-3 = 0 ⇒ х= 3\√2 х₁= 3√2\2
или
х√2+3=0 ⇒ х= - 3\√2 х₂ = -3√2\2