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shinigamis
@shinigamis
July 2022
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найдите корни уравнения (12x^2+1)/(2x+3)=4x-1
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ShirokovP
Verified answer
ОДЗ
x ≠ - 1,5
Решение
12x^2 + 1 - (4x - 1)(2x + 3) = 0
12x^2 + 1 - (8x^2 + 12x - 2x - 3) = 0
12x^2 + 1 - 8x^2 - 10x + 3 = 0
4x^2 - 10x + 4 = 0 /:(2)
2x^2 - 5x + 2 = 0
D = 25 - 16 = 9
x1 = ( 5 + 3)/4 = 8/4 = 2
x2 = ( 5 - 3)/4 = 2/4 = 0,5
Ответ
0,5 ; 2
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Answers & Comments
Verified answer
ОДЗx ≠ - 1,5
Решение
12x^2 + 1 - (4x - 1)(2x + 3) = 0
12x^2 + 1 - (8x^2 + 12x - 2x - 3) = 0
12x^2 + 1 - 8x^2 - 10x + 3 = 0
4x^2 - 10x + 4 = 0 /:(2)
2x^2 - 5x + 2 = 0
D = 25 - 16 = 9
x1 = ( 5 + 3)/4 = 8/4 = 2
x2 = ( 5 - 3)/4 = 2/4 = 0,5
Ответ
0,5 ; 2