Помогите пожалуйста!!!(2/3xy²z)² * (-1 1/2x²z)³ * xyzПолний ответ. Created by toni4ka581. algebra-ru

2x²z)³ * xyzПолний ответ...

toni4ka581 @toni4ka581

August 2022 2 9 Report

Помогите пожалуйста!!!

(2/3xy²z)² * (-1 1/2x²z)³ * xyz
Полний ответ

sangers1959

Verified answer

Объяснение:

$(\frac{2}{3}xy^2z)^2*(-1\frac{1}{2} x^2z)^3*xyz=(\frac{2}{3}xy^2z)^2*(-\frac{3}{2} x^2z)^3*xyz= \\=-(\frac{2}{3})^2x^2y^4z^2*(\frac{3}{2} )^3x^6z^3*xyz=-\frac{4*27}{9*8}x^9y^5z^6=-1,5x^9y^5z^6.$

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ludmilaksenija2005

Объяснение:

(2/3ху^2z)^2×(-1 1/2x^2z)^3×xyz=

=4/9x^2y^4z^2×(-3/2)^3x^6z^3xyz=

= - 4/9x^2y^4z^2×27/8x^6z^3xyz=

= - 3/2x^9y^5z^6= - 1,5x^9y^5z^6

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