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zarinasul
@zarinasul
July 2022
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1. cos2x=0,26
2. sin(x/3)=-0,09
два примера 20 баллов
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Alexandr130398
1. cos2x=0,26
2х=+-arccos0.26 +2пn
x=+-(1/2)arccos0.26 +пn
ответ: (1/2)arccos0.26 +пn; (1/2)arccos0.26 +пn, n принадлежит Z
2) sin(x/3)=-0,09
(x/3)=(-1)^(n) *(-arcsin0.09)+пn
(x/3)=(-1)^(n+1) *arcsin0.09+пn
x=(-1)^(n+1)*3arcsin0.09 +3пn
ответ: =(-1)^(n+1)*3arcsin0.09 +3пn, n принадлежит Z
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Answers & Comments
2х=+-arccos0.26 +2пn
x=+-(1/2)arccos0.26 +пn
ответ: (1/2)arccos0.26 +пn; (1/2)arccos0.26 +пn, n принадлежит Z
2) sin(x/3)=-0,09
(x/3)=(-1)^(n) *(-arcsin0.09)+пn
(x/3)=(-1)^(n+1) *arcsin0.09+пn
x=(-1)^(n+1)*3arcsin0.09 +3пn
ответ: =(-1)^(n+1)*3arcsin0.09 +3пn, n принадлежит Z