November 2021 0 0 Report
ПОМОГИТЕ С ТРИГОНОМЕТРИЕЙ УМОЛЯЮ!50 Б 1)4sin 15° cos 15°-8,5
2)√2 (sin^2 22°30′ - cos^2 22°30′ ) +7
3) (6tg 75°)/√3 (1-tg^2 75°) и вся дробь +2
4)√91 sin2x-4 если sinx=0,3 находится во второй четверти
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