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listopadski
@listopadski
October 2021
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Помогите с решением
2) 3sin ( x/6+π/3) ≤ 1
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vezaytsev
Sin3x*cosπ/6-sinπ/6*cos3x=1
sin(3x-π/6)=1
3x-π/6=π+2πn
3x=π+π/6+2πn=7π/6+2πn
x=7π/18+πn/3
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listopadski
спасибо, если захотите помочь еще загляните на другие мои объявления
vezaytsev
ок
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Answers & Comments
sin(3x-π/6)=1
3x-π/6=π+2πn
3x=π+π/6+2πn=7π/6+2πn
x=7π/18+πn/3