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ilusha011
@ilusha011
July 2022
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√(3-2√2)*(√2+1)
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ArgentumV
√(3-2√2)*(√2+1)
√(2+1-2√2)*(√2+1)
√(1-2√2+2)*(√2+1)
√(1-√2)²*(√2+1)
|(1-√2)|*(√2+1)
(√2-1)*(√2+1)
(√2)²-1²
2-1=1
2 votes
Thanks 3
ilusha011
можешь пояснить, откуда взялся квадрат?
ArgentumV
по формуле a²-2ab+b²=(a-b)². В данном уравнении a=1, b=√2. Т.е., (1-2√2+2) это (1²-2*1*√2+√2²) = (1-√2)²
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Answers & Comments
√(2+1-2√2)*(√2+1)
√(1-2√2+2)*(√2+1)
√(1-√2)²*(√2+1)
|(1-√2)|*(√2+1)
(√2-1)*(√2+1)
(√2)²-1²
2-1=1