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amankyan
@amankyan
August 2022
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Решить показательне неравенства
(1/3)ˣ ≤ 27
Ответ [-3; ∞)
(0,25)ˣ > 16
Ответ (-∞; -2)
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Answers & Comments
Godnessgirl
(1/3)ˣ ≤ 27
(1/3)ˣ≤3³
(1/3)ˣ≤(1/3)^-3
х≥-3
Ответ [-3; ∞)
(0,25)ˣ > 16
(0,5²)ˣ > 2⁴
(1/2)²ˣ > (1/2)^-4
2х<-4
х<-2
Ответ (-∞; -2)
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Answers & Comments
(1/3)ˣ≤3³
(1/3)ˣ≤(1/3)^-3
х≥-3
Ответ [-3; ∞)
(0,25)ˣ > 16
(0,5²)ˣ > 2⁴
(1/2)²ˣ > (1/2)^-4
2х<-4
х<-2
Ответ (-∞; -2)