3 ≤ |2х-3| < 7среднее арифметическое целых решений неравенства. Created by optimus3331. algebra-ru

3 ≤ |2х-3| < 7среднее арифметическое целых решений неравенства...

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|2x-3|≥3⇒
[2x-3≤-3⇒2x≤0⇒x≤0
[2x-3≥3⇒2x≥6⇒x≥3
-7<2x-3<7
-4<2x<10
-2<x<5
x∈(-2;0] U [3;5)
среднее арифметическое (-1+0+3+4):4=6:4=1,5

3 votes Thanks 3

roulen Среднее арифметическое = (-1+0+3+4+5+6+7+8+9)/9=41/9

optimus3331 варианты: 1) 51/10 2) 3/2 3) 49/11 4) 38/7 5) 43/9

optimus3331 Пока твой ответ не подходит

ЕкарныйБабай 3 ≤ |2х-3| < 7
1. 3 ≤ |2х-3|
3 ≤ 2х-3
2x>=6
x>=3
2x-3<=-3
x<=0
x=(-00 0] [3 +00))
2. |2х-3| < 7
2x-3<7
x<5
2x-3>-7
2x>-4
x>-2
-------------- (-2) /////////////////////// (5)------------------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\[0]--------[3]\\\\\\\\\\\\\\\\\\\\\\\\\\\\
(-2 0] U [3 5)
итаго -1 0 3 4
(-1+0+3+4)/4= 6/4= 3/2=1.5
среднее арифм = 1.5 =3/2

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