Ответ:
[tex]\frac{10}{69} < \frac{1}{3\sqrt{3}+\sqrt{2}} < \frac{2}{13}[/tex]
Объяснение:
[tex]1,7 < \sqrt{3} < 1,8\ \ \ |\cdot 3\\\\5,1 < 3\sqrt{3} < 5,4[/tex]
[tex]5,1 < 3\sqrt{3} < 5,4\\\\1,4 < \sqrt{2} < 1,5[/tex]
+________________
[tex]6,5 < 3\sqrt{3}+\sqrt{2} < 6,9\\\\\frac{1}{6,9} < \frac{1}{3\sqrt{3}+\sqrt{2}} < \frac{1}{6,5}\\\\\frac{10}{69} < \frac{1}{3\sqrt{3}+\sqrt{2}} < \frac{10}{65}\\\\\frac{10}{69} < \frac{1}{3\sqrt{3}+\sqrt{2}} < \frac{2}{13}[/tex]
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Answers & Comments
Ответ:
[tex]\frac{10}{69} < \frac{1}{3\sqrt{3}+\sqrt{2}} < \frac{2}{13}[/tex]
Объяснение:
[tex]1,7 < \sqrt{3} < 1,8\ \ \ |\cdot 3\\\\5,1 < 3\sqrt{3} < 5,4[/tex]
[tex]5,1 < 3\sqrt{3} < 5,4\\\\1,4 < \sqrt{2} < 1,5[/tex]
+________________
[tex]6,5 < 3\sqrt{3}+\sqrt{2} < 6,9\\\\\frac{1}{6,9} < \frac{1}{3\sqrt{3}+\sqrt{2}} < \frac{1}{6,5}\\\\\frac{10}{69} < \frac{1}{3\sqrt{3}+\sqrt{2}} < \frac{10}{65}\\\\\frac{10}{69} < \frac{1}{3\sqrt{3}+\sqrt{2}} < \frac{2}{13}[/tex]