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chernych2575
@chernych2575
August 2022
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помогите решить уравнения
sin(2x)=1
2* sin(2pix/3) + 3 =2
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yarovoe
sin(2x)=1 2 sin(2pix/3) + 3 =2
2x=
π/2+2πn 2sin(2πx/3)=2-3
x=π/4+πn , n∈Z 2sin(2πx/3)=-1
sin(2πx/3)=-1/2
(2πx/3)=(-1)ⁿ⁺¹π/6+πn, n∈Z
2πx=(-1)ⁿ⁺¹π/2+3πn, n∈Z
2x=(-1)ⁿ⁺¹1/2+3n, n∈Z
x=(-1)ⁿ⁺¹1/4+1,5n, n∈Z
2 votes
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Answers & Comments
2x=π/2+2πn 2sin(2πx/3)=2-3
x=π/4+πn , n∈Z 2sin(2πx/3)=-1
sin(2πx/3)=-1/2
(2πx/3)=(-1)ⁿ⁺¹π/6+πn, n∈Z
2πx=(-1)ⁿ⁺¹π/2+3πn, n∈Z
2x=(-1)ⁿ⁺¹1/2+3n, n∈Z
x=(-1)ⁿ⁺¹1/4+1,5n, n∈Z