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tamara151220041
@tamara151220041
March 2023
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10 класс
Какой объем бензола (плотность 0,8 г/см3) можно получить из 33.6 л ацетилена (н.у.)? (3 км)
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ol3gzinovev
3С2Н2 = С6Н6 n(C2H2 )= 33.6 / 22.4 =1.5 моль n(C6H6) = 0.5 моль m ( C6H6 ) = 78 * 0.5 = 39 г V ( C6H6) = 39 / 0.8 =48.75 мл
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