1) cos (π/3-3x) = √3/2
π/3-3x = ±π/3 + 2πk? k∈Z
x1 = 2/3πk
x2 = 2/9π + 2/3πk
2) замена tgx = y решить кв ур-ие x= arctg y
3) ∅ т.к. sin x ≤ 1
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1) cos (π/3-3x) = √3/2
π/3-3x = ±π/3 + 2πk? k∈Z
x1 = 2/3πk
x2 = 2/9π + 2/3πk
2) замена tgx = y решить кв ур-ие x= arctg y
3) ∅ т.к. sin x ≤ 1