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madmaria
@madmaria
July 2022
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y=-2tg (П/3-3x)-4 в точке с абциссой
x
0=0
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flora200226
Y=4x+5; y=x^2+bx+c; x0=-2f(0)=5 f(0)=c; c=5f(-2)=4*(-2)+5=-3; f(-2)=(-2)^2-2b+c=4-2b+c;4-2b+c=-3 c=5 postablyaem4-2b+5=-3-2b=-12 b=6
otwet: b+c=5+6=11
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