3. — 4. — 4-5 А) 4 12
ПН 1 2 2 3. — 20
5 — 2. — 1. — 29
Б)
Задание 2
7. — 12 > За H2O
5 — 2. — 4 — 20
Уровень В
2.2.
7y < 42
12. 3
- 2y < 4
18 –
30
4y > 12
8y < 48
3.2.
- 3у «12
7y -14 20
4.2.
2y = 8
7 - 2y = 0
5.2.
5 – 20 <0
2 — 80
6.2.
2y-320​
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