3(-4х+1)(х-1)+2(6*х-4)(х+3)=50 5(2х+3)(х+2)-2(5х-4)(х-1)=32. Created by khoruzhy2015. algebra-ru

3(-4х+1)(х-1)+2(6*х-4)(х+3)=50 5(2х+3)(х+2)-2(5х-4)(х-1)=32...

khoruzhy2015 @khoruzhy2015

July 2022 1 12 Report

3(-4х+1)(х-1)+2(6*х-4)(х+3)=50
5(2х+3)(х+2)-2(5х-4)(х-1)=32

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lakOR555 3(-4х²+4х+х-1)+2(6х²+18х-4х-12)=50
-12х²+12х+3х-3+12х²+36х-8х-24=50
43х-27=50
43х=77
х=77/43 =1 34/43

5(2х²+4х+3х+6)-2(5х²-5х-4х+4)=32
10х²+20х+15х+30-10х²+10х+8х-8=32
53х+22=32
53х=10
х=10/53

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