Ответ:
(3х + 5у)² - (4х - 1)(2х + 3) = 9x²+25y²+30xy - (8x²+12x-2x-3) = 9x²+25y²+30xy-8x²-12x+2x+3 = x²+25y²+30xy-10x+3 = x(x+30y-10)+25y²+3
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Ответ:
(3х + 5у)² - (4х - 1)(2х + 3) = 9x²+25y²+30xy - (8x²+12x-2x-3) = 9x²+25y²+30xy-8x²-12x+2x+3 = x²+25y²+30xy-10x+3 = x(x+30y-10)+25y²+3