[tex]\displaystyle 2\frac{1}{13}*(5-11\frac{2}{13})+11\frac{2}{13}*(2\frac{1}{3}-5)=\frac{27}{13}(5-\frac{145}{13})+\frac{145}{13}(\frac{7}{3}-5)=\\\\\frac{27}{13}(-\frac{80}{13})+\frac{145}{13}(-\frac{8}{3})=-\frac{2160}{169}-\frac{1160}{39}=-\frac{21560}{507}=-42\frac{266}{507}[/tex]
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[tex]\displaystyle 2\frac{1}{13}*(5-11\frac{2}{13})+11\frac{2}{13}*(2\frac{1}{3}-5)=\frac{27}{13}(5-\frac{145}{13})+\frac{145}{13}(\frac{7}{3}-5)=\\\\\frac{27}{13}(-\frac{80}{13})+\frac{145}{13}(-\frac{8}{3})=-\frac{2160}{169}-\frac{1160}{39}=-\frac{21560}{507}=-42\frac{266}{507}[/tex]