[tex]\frac{2}{3}(1\frac{1}{2}x+\frac{3}{5})-\frac{4}{5}(\frac{5}{12} x - \frac{1}{2})=1\frac{3}{5} \\\frac{2}{3}(\frac{3}{2}x+\frac{3}{5})-\frac{4}{5}(\frac{5}{12} x - \frac{1}{2})=\frac{8}{5}\\\frac{2}{3}*\frac{3}{2}x+\frac{2}{3}* \frac{3}{5}-\frac{4}{5}(\frac{5}{12} x - \frac{1}{2})=\frac{8}{5} \\x+\frac{2}{5}-\frac{4}{5}*\frac{5}{12} x +\frac{4}{5} * \frac{1}{2}=\frac{8}{5} \\x+\frac{2}{5}-\frac{1}{3} x +\frac{2}{5} =\frac{8}{5} \\\frac{2}{3}x=\frac{4}{5} \\ x = \frac{4*3}{2*5} = \frac{12}{10} = 1.2[/tex]
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[tex]\frac{2}{3}(1\frac{1}{2}x+\frac{3}{5})-\frac{4}{5}(\frac{5}{12} x - \frac{1}{2})=1\frac{3}{5} \\\frac{2}{3}(\frac{3}{2}x+\frac{3}{5})-\frac{4}{5}(\frac{5}{12} x - \frac{1}{2})=\frac{8}{5}\\\frac{2}{3}*\frac{3}{2}x+\frac{2}{3}* \frac{3}{5}-\frac{4}{5}(\frac{5}{12} x - \frac{1}{2})=\frac{8}{5} \\x+\frac{2}{5}-\frac{4}{5}*\frac{5}{12} x +\frac{4}{5} * \frac{1}{2}=\frac{8}{5} \\x+\frac{2}{5}-\frac{1}{3} x +\frac{2}{5} =\frac{8}{5} \\\frac{2}{3}x=\frac{4}{5} \\ x = \frac{4*3}{2*5} = \frac{12}{10} = 1.2[/tex]