[tex]\displaystyle \frac{x+35}{x^2-xy}-\frac{y+35}{xy-y^2}=\frac{x+35}{x(x-y)}-\frac{y+35}{y(x-y)}=\frac{y(x+35)-x(y+35)}{xy(x-y)}=\frac{xy+35y-xy-35x}{xy(x-y)}=\\\\\frac{-35(-y+x)}{xy(x-y)}=\frac{-35}{xy}=-\frac{35}{xy}[/tex]
[tex]\frac{x+35}{x^2-xy} -\frac{y+35}{xy-y^2}=\frac{x+35}{x(x-y)} -\frac{y+35}{y(x-y)}= \frac{xy+35y-xy-35x}{xy(x-y)}=\frac{35(y-x)}{xy(x-y)}=\frac{-35}{xy}[/tex]
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[tex]\displaystyle \frac{x+35}{x^2-xy}-\frac{y+35}{xy-y^2}=\frac{x+35}{x(x-y)}-\frac{y+35}{y(x-y)}=\frac{y(x+35)-x(y+35)}{xy(x-y)}=\frac{xy+35y-xy-35x}{xy(x-y)}=\\\\\frac{-35(-y+x)}{xy(x-y)}=\frac{-35}{xy}=-\frac{35}{xy}[/tex]
[tex]\frac{x+35}{x^2-xy} -\frac{y+35}{xy-y^2}=\frac{x+35}{x(x-y)} -\frac{y+35}{y(x-y)}= \frac{xy+35y-xy-35x}{xy(x-y)}=\frac{35(y-x)}{xy(x-y)}=\frac{-35}{xy}[/tex]