[tex]1) f(-5)=\dfrac{-5}{-5+1} =1,2\\\\2) f(x_0)=\dfrac{1}{3} = > \dfrac{1}{3}= \dfrac{x_0}{x_0+1}\\\\x_0+1=3x_0;x_0\neq-1\\2x_0=1\\x_0=0,5[/tex]