[tex]\displaystyle\bf\\\left \{ {{ \frac{x + 2}{6} - \frac{y - 3}{4} = 1 \: \: | \times 12} \atop { \frac{x - 2}{4} - \frac{y - 4}{2} = 1 \: \: | \times 4}} \right. \\ \displaystyle\bf\\\left \{ {{2(x + 2) - 3(y - 3) = 12} \atop {x - 2 - 2(y - 4) = 4 }} \right. \\ \displaystyle\bf\\\left \{ {{2x + 4 - 3y + 9 = 12} \atop {x - 2 - 2y + 8 = 4 }} \right. \\ \displaystyle\bf\\\left \{ {{2x - 3y = - 1} \atop {x - 2y = - 2 \: \: | \times ( - 2)}} \right. \\ \displaystyle\bf\\ + \left \{ {{2x - 3y = - 1} \atop { - 2x + 4y = 4 }} \right. \\ \\ 4y - 3y = 4 - 1 \\ y = 3 \\ \\ x - 2 \times 3 = - 2 \\ x - 6 = - 2 \\ x = - 2 + 6 \\ x = 4[/tex]

Ответ: ( 4 ; 3 )