Verified answer

Ответ:

[tex]-11\sqrt{2} < -6\sqrt{5} < -7\sqrt{3}[/tex]

Объяснение:

[tex]-7\sqrt{3}=-\sqrt{7^2*3}=-\sqrt{49*3}=-\sqrt{147}\\\\-11\sqrt{2}=-\sqrt{11^2*2}=-\sqrt{121*2}=-\sqrt{242}\\\\-6\sqrt{5}=-\sqrt{6^2*5}=-\sqrt{36*5}=-\sqrt{180}\\\\\\147 < 180 < 242\; = > \\\\ = > \sqrt{147} < \sqrt{180} < \sqrt{242}\; = > \\\\= > -\sqrt{242} < -\sqrt{180} < -\sqrt{147}\;\; = > \\\\= > -11\sqrt{2} < -6\sqrt{5} < -7\sqrt{3}[/tex]