i
[tex]а) 4y^2=12,25 \\
y^2=3,0625 \\
y=\pm1,75 \\ \\
b) l^2+2l-8=0 \\
D=4+4\cdot8=36 \\
l_{1,2}=\dfrac{-2\pm6}{2}=-1\pm3=(2;-4) \\ \\
c) 9y^2+18y+5=p \\
D=18^2-4\cdot5\cdot9=144 \\
y_{1,2}=\dfrac{-18\pm12}{18}=(\dfrac{-1}{3};,\dfrac{-5}{3})[/tex]
[tex](z-2)^2+2z=7(z-2) \\
z^2-2z+4=7z-14 \\
z^2-9z+18=0 \\
D=81-4\cdot18=9 \\
z_{1,2}=\dfrac{9\pm3}{2}=(6; 3) \\
z_1+z_2=6+3=9[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
i
[tex]а) 4y^2=12,25 \\
y^2=3,0625 \\
y=\pm1,75 \\ \\
b) l^2+2l-8=0 \\
D=4+4\cdot8=36 \\
l_{1,2}=\dfrac{-2\pm6}{2}=-1\pm3=(2;-4) \\ \\
c) 9y^2+18y+5=p \\
D=18^2-4\cdot5\cdot9=144 \\
y_{1,2}=\dfrac{-18\pm12}{18}=(\dfrac{-1}{3};,\dfrac{-5}{3})[/tex]
[tex](z-2)^2+2z=7(z-2) \\
z^2-2z+4=7z-14 \\
z^2-9z+18=0 \\
D=81-4\cdot18=9 \\
z_{1,2}=\dfrac{9\pm3}{2}=(6; 3) \\
z_1+z_2=6+3=9[/tex]