Ответ:

3.

[tex]( {y}^{2} {)}^{3} = {y}^{6} [/tex]

[tex]( {y}^{7} {)}^{5} = {y}^{35} [/tex]

[tex]( {y}^{ - 7} {)}^{ - 3} = y {}^{21} [/tex]

4)

[tex] {( {x}^{7} )}^{2} \times {( {x}^{5}) }^{6} = {x}^{14} \times {x}^{30} = {x}^{44} [/tex]

[tex] {( {p}^{2} )}^{6} \div {p}^{9} = {p}^{12} \div {p}^{9} = {p}^{3} [/tex]

[tex] {( {y}^{ - 5}) }^{2} \div ( {y}^{ - 6} \times {y}^{4} ) = {y}^{ - 10} \div {y}^{ - 2} = {y}^{ - 10 + 2} = {y}^{ - 8} [/tex]

Сделай лучшим пж)