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thenightisstillyoung
@thenightisstillyoung
July 2022
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найти координаты вектора 1/3 a+b если а {0, 3, -6} b {5, -2, 1}
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ekaterinaziza
Х=1/3(0+5)=1/3*5=5/3=1 2/3
y=1/3(3-2)=1/3*1=1/3
z=1/3(-6+1)=1/3*(-5)=-5/3=-1 2/3
(1 2/3;1/3;-1 2/3)
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Answers & Comments
y=1/3(3-2)=1/3*1=1/3
z=1/3(-6+1)=1/3*(-5)=-5/3=-1 2/3
(1 2/3;1/3;-1 2/3)