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asdf561
@asdf561
September 2021
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ДАЮ 50 ПКТ ЗА ПРАВИЛЬНОЕ РЕШЕНИЕ!!
cos(arctg(1/3)+ arctg (-√3)
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Cos(arctg(1/3)-arctg(√3))=cos(arctg(1/3)cos60+sin60sin(arctg(1/3))=
tgx=1/3
sin^2x/cos^2x=1/9
9sin^2x=1-sin^2x
sinx=√10/10
cosx=3√10/10
=3√10/20+√30/20=√30/20(√3+1)
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Answers & Comments
tgx=1/3
sin^2x/cos^2x=1/9
9sin^2x=1-sin^2x
sinx=√10/10
cosx=3√10/10
=3√10/20+√30/20=√30/20(√3+1)