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ufim122
@ufim122
August 2022
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у=-2cos3x+1. Найдите значения f(π), f(π/4), f(-π/3), f(0)
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NaZaRiO24
Y=-2cos3x+1
y(π)=-2cos3π+1=-2cosπ+1=-2*(-1)+1=2+1=3
y(π/4)=-2cos3π/4+1=-2*(-√2/2)+1=√2+1
y(-π/3)=-2cos(-π)+1=-2*(-4)+1=2+1=3
y(0)=-2cos0+1=-2*1+1=-2+1=-1
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sedinalana
Verified answer
F(pi)=-2*-1+1=3 f(pi/4)=-2*(-sqrt2/2)+1= sqrt2+1 f(-pi/3)=-2*-1+1=3 f(0)=-2*1+1=-1
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Answers & Comments
y(π)=-2cos3π+1=-2cosπ+1=-2*(-1)+1=2+1=3
y(π/4)=-2cos3π/4+1=-2*(-√2/2)+1=√2+1
y(-π/3)=-2cos(-π)+1=-2*(-4)+1=2+1=3
y(0)=-2cos0+1=-2*1+1=-2+1=-1
Verified answer
F(pi)=-2*-1+1=3 f(pi/4)=-2*(-sqrt2/2)+1= sqrt2+1 f(-pi/3)=-2*-1+1=3 f(0)=-2*1+1=-1