3. Mr( Fe(OH)3 ) = 56 + 3×16 + 3×1 = 107
4. Mr( CaCO3 ) = 40 + 12 + 3×16 = 100
W(Ca) = 40×1/100 × 100% = 40,01 або 40%
W(C) = 1×12/100 × 100% = 11,99 або 12%
W(O) = 100- (40%+12%) = 48%
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Answers & Comments
3. Mr( Fe(OH)3 ) = 56 + 3×16 + 3×1 = 107
4. Mr( CaCO3 ) = 40 + 12 + 3×16 = 100
W(Ca) = 40×1/100 × 100% = 40,01 або 40%
W(C) = 1×12/100 × 100% = 11,99 або 12%
W(O) = 100- (40%+12%) = 48%