3. How many grams are there in
1.806. 1022 molecules of MgCl2 ппллииззззззззззззззз
1.806. 1022 molecules of MgCl2 ппллииззззззззззззззз
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N=NA*n;
n=N/NA= 1.806*10^22/6.02*10^23=0.03
n=m/M;
m(MgCl2)=95*0.03=2.85(g)
Ответ: 2.85g