Решите уравнение:
f ' (x) * g ' (x) = 0, если f (x)= x^3 - 6x, g (x)= (1/3)* корень из x
f ' (x) * g ' (x) = 0, если f (x)= x^3 - 6x, g (x)= (1/3)* корень из x
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Answers & Comments
g¹(x)=1/(6√x)
f¹(x)*g¹(x)=0
(3x²-6)1/(6√x)=0
x≠0
3x²-6=0
3x²=6
x²=2
x₁=√2 x₂=-√2