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Lutiypacan1437
@Lutiypacan1437
August 2022
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Найдите решения уравнения tgx=-√3/3, которые принадлежат отрезку [-p;3p]
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kirillgrans
Tgx=-√3/3
[-пи;3пи]
x=-пи/6+пи*n
-пи<=-пи/6+пи*n<=3пи
-1<=-1/6+n<=3
-5/6<=n<=19/6
n=0,1,2,3.
x=-пи/6,x=5пи/6,x=11пи/6,x=17пи/6.
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Answers & Comments
x=-пи/6+пи*n
-пи<=-пи/6+пи*n<=3пи
-1<=-1/6+n<=3
-5/6<=n<=19/6
n=0,1,2,3.
x=-пи/6,x=5пи/6,x=11пи/6,x=17пи/6.