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Cooper7201
@Cooper7201
April 2021
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1. Вычислите 5*25^(1/2) - (1/81)^(-1/2)
2. Вычислите 2*(1/64^(1/3))
наверно ничего не понятно поэтому сфотаю.
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svetazuna
1.
5 * 25^(1/2) - 1/81^(-1/4) = 5 * √25 - 81^(1/4) = 5 * 5 - ⁴√81 = 25 - 3 = 22
(1),
2.
2 * (1/64)^(-1/3) + 32^(1/5) = 2 * 64^(1/3) + ⁵√32 =
= 2 * ³√64 + ⁵√32 = 2 * 4 + 2 = 8 + 2 = 10
(2),
3.
(а^(3/4))^(-1) * a^(1/4) : a^(-3 1/2) =
= (а^(-3/4) * a^(1/4) : a^(-7/2) =
= а^(-3/4 + 1/4 - (-7/2)) =
= a^(-3/4 + 1/4 + 7/2) =
= a^(-3/4 + 1/4 + 14/4) =
= a^(12/4) = a³
(4)
,
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Cooper7201
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Answers & Comments
5 * 25^(1/2) - 1/81^(-1/4) = 5 * √25 - 81^(1/4) = 5 * 5 - ⁴√81 = 25 - 3 = 22 (1),
2.
2 * (1/64)^(-1/3) + 32^(1/5) = 2 * 64^(1/3) + ⁵√32 =
= 2 * ³√64 + ⁵√32 = 2 * 4 + 2 = 8 + 2 = 10 (2),
3.
(а^(3/4))^(-1) * a^(1/4) : a^(-3 1/2) =
= (а^(-3/4) * a^(1/4) : a^(-7/2) =
= а^(-3/4 + 1/4 - (-7/2)) =
= a^(-3/4 + 1/4 + 7/2) =
= a^(-3/4 + 1/4 + 14/4) =
= a^(12/4) = a³ (4),