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SkipperFS
@SkipperFS
August 2022
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вычислить. sin (11п/3) +tg585° - cos (19п/3)
подробнее объясните пожалуйста решение
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Lesben
Sin(11π/3)+tg585°-cos(19π/3)=sin(12π/3-π/3)+tg(540°+45°)-cos(18π/3+π/3)=
=sin(4π-π/3)+tg(3.180°+45°)-cos(6π+π/3)=sin(-π/3)+tg45°-cos(π/3)=
=-sin(π/3)+1-cos(π/3)=(-√3)/2+1-1/2=1/2-√3/2=(1-√3)/2
(sin(x+2kπ)=sinx, tg(x+kπ)=tgx, cos(x+2kπ)=cosx, tg45°=1,cos(π/3)=1/2,
sin(π/3)=√3/2)
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SkipperFS
я честно не понял как вы это решили (
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Answers & Comments
=sin(4π-π/3)+tg(3.180°+45°)-cos(6π+π/3)=sin(-π/3)+tg45°-cos(π/3)=
=-sin(π/3)+1-cos(π/3)=(-√3)/2+1-1/2=1/2-√3/2=(1-√3)/2
(sin(x+2kπ)=sinx, tg(x+kπ)=tgx, cos(x+2kπ)=cosx, tg45°=1,cos(π/3)=1/2,
sin(π/3)=√3/2)