Ответ:
Mr(CuO)= Ar(Cu)+Ar(O)= 64+16= 80
W(Cu)=Ar(Cu)/Mr(CuO)*100=80%
Mr(Cu2O) = 2Ar(Cu)*Ar(O)=2*64 +16 =144
W(Cu)=128/144*100=88,8%
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Ответ:
Mr(CuO)= Ar(Cu)+Ar(O)= 64+16= 80
W(Cu)=Ar(Cu)/Mr(CuO)*100=80%
Mr(Cu2O) = 2Ar(Cu)*Ar(O)=2*64 +16 =144
W(Cu)=128/144*100=88,8%