Помогите решить уравнение. 2cos(Пи/3-x)=1
2cos(п/3-x)=1cos(п/3-x)=1/2cos(x-п/3)=1/2x-п/3 = +-arccos(1/2)+2пkx-п/3=+-п/3+2пkx=2п/3+2пk; x=2пk
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2cos(п/3-x)=1
cos(п/3-x)=1/2
cos(x-п/3)=1/2
x-п/3 = +-arccos(1/2)+2пk
x-п/3=+-п/3+2пk
x=2п/3+2пk; x=2пk