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gffcv
@gffcv
July 2022
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1/(x+1) + 1/(3-x)<=1
Как решать ....объясните....
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sedinalana
Verified answer
1/(x+1)+1/(3-x)-1≤0
(3-x+x+1-3x+x²-3+x)/(x+1)(3-x)≤0
(x²-2x+1)/(x+1)(3-x)≤0
(x-1)²/(x+1)(3-x)≤0
x=1 x=-1 x=3
_ + + _
----------------(-1)-------------[1]---------------(3)------------------
x∈(-∞;-1) U (3;∞) U {1}
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gffcv
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sedinalana
зачем?Оно сдесь не нужно.
gffcv
Нужно
gffcv
Мне
gffcv
У тебя ошибка
gffcv
Должно получится x^2-2x+1
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Answers & Comments
Verified answer
1/(x+1)+1/(3-x)-1≤0(3-x+x+1-3x+x²-3+x)/(x+1)(3-x)≤0
(x²-2x+1)/(x+1)(3-x)≤0
(x-1)²/(x+1)(3-x)≤0
x=1 x=-1 x=3
_ + + _
----------------(-1)-------------[1]---------------(3)------------------
x∈(-∞;-1) U (3;∞) U {1}