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lerapavlichenk
@lerapavlichenk
July 2022
1
8
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найдите наибольшее и наименьшее значение функции y=2/3 x√x -2x на отрезке [1;9]
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mikael2
y=2/3 x√x -2x на отрезке [1;9]
y(1)=2/3-2=-1 1/3=
-4/3
y(9)=18-18=
0
y'=2/3*3/2√x-2=√x-2 √x-2=yfb,j0 √x=2 x=4
y(4)=2/3*4*2-2*4=16/3-8=
-8/3
наиб. 0
наим. -8/3
0 votes
Thanks 2
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Answers & Comments
y(1)=2/3-2=-1 1/3=-4/3
y(9)=18-18=0
y'=2/3*3/2√x-2=√x-2 √x-2=yfb,j0 √x=2 x=4
y(4)=2/3*4*2-2*4=16/3-8=-8/3
наиб. 0
наим. -8/3