Ответ:
1)
дано
m(Fe(OH)3 = 53.5 g
--------------------
m(Fe2(SO4)3) = ?
2Fe(OH)3 + 3H2SO4-->Fe2(SO4)3+6H2O
M(Fe(OH)3) = 107 g/ mol
n(Fe(OH)3) = m/M = 53.5 / 107 = 0.5 mol
2n(Fe(OH)3) = n(Fe2(SO4)3)
n(Fe2(SO4)3) = 0.5 / 2 =0.25 mol
M(Fe2(SO4)3) = 400 g/mol
m(Fe2(SO4)3) = n*M = 0.25 * 400 = 100 g
ответ 100 гр
2)
m(CaCO3) = 20 g
-------------------
m(CaCL2) - ?
CaCO3+2HCL-->CaCL2+H2O+CO2
M(CaCO3) = 100 g/mol
n(CaCO3) = m/M = 20 / 100 = 0.2 mol
n(CaCO3) = n(CaCL2)
n(CaCL2) = 0.2 mol
ответ 0.2 mol
Объяснение:
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Answers & Comments
Ответ:
1)
дано
m(Fe(OH)3 = 53.5 g
--------------------
m(Fe2(SO4)3) = ?
2Fe(OH)3 + 3H2SO4-->Fe2(SO4)3+6H2O
M(Fe(OH)3) = 107 g/ mol
n(Fe(OH)3) = m/M = 53.5 / 107 = 0.5 mol
2n(Fe(OH)3) = n(Fe2(SO4)3)
n(Fe2(SO4)3) = 0.5 / 2 =0.25 mol
M(Fe2(SO4)3) = 400 g/mol
m(Fe2(SO4)3) = n*M = 0.25 * 400 = 100 g
ответ 100 гр
2)
дано
m(CaCO3) = 20 g
-------------------
m(CaCL2) - ?
CaCO3+2HCL-->CaCL2+H2O+CO2
M(CaCO3) = 100 g/mol
n(CaCO3) = m/M = 20 / 100 = 0.2 mol
n(CaCO3) = n(CaCL2)
n(CaCL2) = 0.2 mol
ответ 0.2 mol
Объяснение: