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Lera123115
@Lera123115
August 2022
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Можно пожалуйста с объяснением:
Приведите многочлен к стандартному виду и найдите его значение.
m^4-3m^3n+m^2n^2-m^3n-4m^2n^2 при m=-1/2, n=1/3
( ^ -значит степень)
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гюйс
Verified answer
M^4 -
3m³n
+m²n² -
m³n
- 4m²n²=m^4 - 4m³n - 3m²n²=m²(m² - 4mn - 3n²)
при m= - 1/2, n=1/3
(-1/2)² * ((-1/2)² - 4*( -1/2)*1/3 - 3*(1/3)²)=1/4*(1/4+2/3 - 1/3)=1/4(1/4+1/3)=1/4 * (3/12 +4/12)=1/4 * 7/12=7/48
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Lera123115
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Answers & Comments
Verified answer
M^4 - 3m³n +m²n² - m³n - 4m²n²=m^4 - 4m³n - 3m²n²=m²(m² - 4mn - 3n²)при m= - 1/2, n=1/3
(-1/2)² * ((-1/2)² - 4*( -1/2)*1/3 - 3*(1/3)²)=1/4*(1/4+2/3 - 1/3)=1/4(1/4+1/3)=1/4 * (3/12 +4/12)=1/4 * 7/12=7/48