12. [tex]\frac{4b^{2} +20b}{25+10b+b^{2} }=\frac{4b(b+5)}{(5+b)^{2} } =\frac{4b}{5+b}[/tex]

10. [tex]|2*(-\frac{5}{6})|=|-\frac{10}{6} |=1\frac{4}{6}=1\frac{2}{3}[/tex]

8. [tex]0,25^{log_{0,5}4 } =0,25^{-2} =(\frac{1}{4})^{-2} =16[/tex]

Verified answer

Объяснение:

12.

(4b²+20b)/(25+10b+b²)=

=(4b(b+5))/((5+b)²)=4b/(5+b)

10.

|2•(-5/6)|=|-5/3|=5/3=1 2/3

8.

log(0,5)4 log2`¹(2²)

0,25 =(1/4) =(1/4)`²=4²=16